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tf.reduce_any(input_tensor, axis=None, keep_dims=False, name=None, reduction_indices=None)

tf.reduce_any(input_tensor, axis=None, keep_dims=False, name=None, reduction_indices=None)

See the guide: Math > Reduction

Computes the "logical or" of elements across dimensions of a tensor.

Reduces input_tensor along the dimensions given in axis. Unless keep_dims is true, the rank of the tensor is reduced by 1 for each entry in axis. If keep_dims is true, the reduced dimensions are retained with length 1.

If axis has no entries, all dimensions are reduced, and a tensor with a single element is returned.

For example:

# 'x' is [[True,  True]
#         [False, False]]
tf.reduce_any(x) ==> True
tf.reduce_any(x, 0) ==> [True, True]
tf.reduce_any(x, 1) ==> [True, False]

Args:

  • input_tensor: The boolean tensor to reduce.
  • axis: The dimensions to reduce. If None (the default), reduces all dimensions.
  • keep_dims: If true, retains reduced dimensions with length 1.
  • name: A name for the operation (optional).
  • reduction_indices: The old (deprecated) name for axis.

Returns:

The reduced tensor.

numpy compatibility

Equivalent to np.any

Defined in tensorflow/python/ops/math_ops.py.

© 2017 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/api_docs/python/tf/reduce_any