tf.is_strictly_increasing(x, name=None)

tf.is_strictly_increasing(x, name=None)

See the guides: Asserts and boolean checks, Framework (contrib)

Returns True if x is strictly increasing.

Elements of x are compared in row-major order. The tensor [x[0],...] is strictly increasing if for every adjacent pair we have x[i] < x[i+1]. If x has less than two elements, it is trivially strictly increasing.

See also: is_non_decreasing

Args:

• x: Numeric Tensor.
• name: A name for this operation (optional). Defaults to "is_strictly_increasing"

Returns:

Boolean Tensor, equal to True iff x is strictly increasing.

Raises:

• TypeError: if x is not a numeric tensor.

Defined in tensorflow/python/ops/check_ops.py.