tensorflow::ops::SparseSegmentSum

#include <math_ops.h>

Computes the sum along sparse segments of a tensor.

Summary

Read the section on Segmentation for an explanation of segments.

Like SegmentSum, but segment_ids can have rank less than data's first dimension, selecting a subset of dimension 0, specified by indices.

For example:

```prettyprint c = tf.constant([[1,2,3,4], [-1,-2,-3,-4], [5,6,7,8]])

Select two rows, one segment.

tf.sparse_segment_sum(c, tf.constant([0, 1]), tf.constant([0, 0])) ==> [[0 0 0 0]]

Select two rows, two segment.

tf.sparse_segment_sum(c, tf.constant([0, 1]), tf.constant([0, 1])) ==> [[ 1 2 3 4] [-1 -2 -3 -4]]

Select all rows, two segments.

tf.sparse_segment_sum(c, tf.constant([0, 1, 2]), tf.constant([0, 0, 1])) ==> [[0 0 0 0] [5 6 7 8]]

Which is equivalent to:

tf.segment_sum(c, tf.constant([0, 0, 1])) ```

Arguments:

• scope: A Scope object
• indices: A 1-D tensor. Has same rank as segment_ids.
• segment_ids: A 1-D tensor. Values should be sorted and can be repeated.

Returns:

• Output: Has same shape as data, except for dimension 0 which has size k, the number of segments.

Public attributes

::tensorflow::Output output

Public functions

 SparseSegmentSum(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input data,
  ::tensorflow::Input indices,
  ::tensorflow::Input segment_ids
)

::tensorflow::Node * node() const 

operator::tensorflow::Input() const 

operator::tensorflow::Output() const