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tensorflow::ops::ArgMin

#include <math_ops.h>

Returns the index with the smallest value across dimensions of a tensor.

Summary

Arguments:

  • scope: A Scope object
  • dimension: int32, 0 <= dimension < rank(input). Describes which dimension of the input Tensor to reduce across. For vectors, use dimension = 0.

Returns:

Constructors and Destructors
ArgMin(const ::tensorflow::Scope & scope, ::tensorflow::Input input, ::tensorflow::Input dimension)
Public attributes
output
Public functions
node() const
::tensorflow::Node *
operator::tensorflow::Input() const
operator::tensorflow::Output() const

Public attributes

output

::tensorflow::Output output

Public functions

ArgMin

 ArgMin(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input input,
  ::tensorflow::Input dimension
)

node

::tensorflow::Node * node() const 

operator::tensorflow::Input

operator::tensorflow::Input() const 

operator::tensorflow::Output

operator::tensorflow::Output() const 

© 2017 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/api_docs/cc/class/tensorflow/ops/arg-min.html