numpy.ma.getmask(a)
[source]
Return the mask of a masked array, or nomask.
Return the mask of a
as an ndarray if a
is a MaskedArray
and the mask is not nomask
, else return nomask
. To guarantee a full array of booleans of the same shape as a, use getmaskarray
.
Parameters: |
a : array_like Input |
---|
See also
getdata
getmaskarray
>>> import numpy.ma as ma >>> a = ma.masked_equal([[1,2],[3,4]], 2) >>> a masked_array(data = [[1 --] [3 4]], mask = [[False True] [False False]], fill_value=999999) >>> ma.getmask(a) array([[False, True], [False, False]], dtype=bool)
Equivalently use the MaskedArray
mask
attribute.
>>> a.mask array([[False, True], [False, False]], dtype=bool)
Result when mask == nomask
>>> b = ma.masked_array([[1,2],[3,4]]) >>> b masked_array(data = [[1 2] [3 4]], mask = False, fill_value=999999) >>> ma.nomask False >>> ma.getmask(b) == ma.nomask True >>> b.mask == ma.nomask True
© 2008–2017 NumPy Developers
Licensed under the NumPy License.
https://docs.scipy.org/doc/numpy-1.12.0/reference/generated/numpy.ma.getmask.html