numpy.ma.choose(indices, choices, out=None, mode='raise')
[source]
Use an index array to construct a new array from a set of choices.
Given an array of integers and a set of n choice arrays, this method will create a new array that merges each of the choice arrays. Where a value in a
is i, the new array will have the value that choices[i] contains in the same place.
Parameters: |
a : ndarray of ints This array must contain integers in choices : sequence of arrays Choice arrays. The index array and all of the choices should be broadcastable to the same shape. out : array, optional If provided, the result will be inserted into this array. It should be of the appropriate shape and mode : {‘raise’, ‘wrap’, ‘clip’}, optional Specifies how out-of-bounds indices will behave.
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Returns: |
merged_array : array |
See also
choose
>>> choice = np.array([[1,1,1], [2,2,2], [3,3,3]]) >>> a = np.array([2, 1, 0]) >>> np.ma.choose(a, choice) masked_array(data = [3 2 1], mask = False, fill_value=999999)
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https://docs.scipy.org/doc/numpy-1.12.0/reference/generated/numpy.ma.choose.html