numpy.setdiff1d(ar1, ar2, assume_unique=False)[source]
Find the set difference of two arrays.
Return the sorted, unique values in ar1
that are not in ar2
.
Parameters: |
ar1 : array_like Input array. ar2 : array_like Input comparison array. assume_unique : bool If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False. |
---|---|
Returns: |
setdiff1d : ndarray Sorted 1D array of values in |
See also
numpy.lib.arraysetops
>>> a = np.array([1, 2, 3, 2, 4, 1]) >>> b = np.array([3, 4, 5, 6]) >>> np.setdiff1d(a, b) array([1, 2])
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https://docs.scipy.org/doc/numpy-1.11.0/reference/generated/numpy.setdiff1d.html