numpy.logical_xor(x1, x2[, out]) =
Compute the truth value of x1 XOR x2, element-wise.
Parameters: |
x1, x2 : array_like Logical XOR is applied to the elements of |
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Returns: |
y : bool or ndarray of bool Boolean result of the logical XOR operation applied to the elements of |
See also
>>> np.logical_xor(True, False) True >>> np.logical_xor([True, True, False, False], [True, False, True, False]) array([False, True, True, False], dtype=bool)
>>> x = np.arange(5) >>> np.logical_xor(x < 1, x > 3) array([ True, False, False, False, True], dtype=bool)
Simple example showing support of broadcasting
>>> np.logical_xor(0, np.eye(2)) array([[ True, False], [False, True]], dtype=bool)
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https://docs.scipy.org/doc/numpy-1.10.1/reference/generated/numpy.logical_xor.html