numpy.any(a, axis=None, out=None, keepdims=False)[source]
Test whether any array element along a given axis evaluates to True.
Returns single boolean unless axis
is not None
Parameters: |
a : array_like Input array or object that can be converted to an array. axis : None or int or tuple of ints, optional Axis or axes along which a logical OR reduction is performed. The default ( New in version 1.7.0. If this is a tuple of ints, a reduction is performed on multiple axes, instead of a single axis or all the axes as before. out : ndarray, optional Alternate output array in which to place the result. It must have the same shape as the expected output and its type is preserved (e.g., if it is of type float, then it will remain so, returning 1.0 for True and 0.0 for False, regardless of the type of keepdims : bool, optional If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the original |
---|---|
Returns: |
any : bool or ndarray A new boolean or |
See also
ndarray.any
all
Not a Number (NaN), positive infinity and negative infinity evaluate to True
because these are not equal to zero.
>>> np.any([[True, False], [True, True]]) True
>>> np.any([[True, False], [False, False]], axis=0) array([ True, False], dtype=bool)
>>> np.any([-1, 0, 5]) True
>>> np.any(np.nan) True
>>> o=np.array([False]) >>> z=np.any([-1, 4, 5], out=o) >>> z, o (array([ True], dtype=bool), array([ True], dtype=bool)) >>> # Check now that z is a reference to o >>> z is o True >>> id(z), id(o) # identity of z and o (191614240, 191614240)
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https://docs.scipy.org/doc/numpy-1.10.1/reference/generated/numpy.any.html