The substring()
method returns a subset of a string
between one index and another, or through the end of the string.
str.substring(indexStart[, indexEnd])
indexStart
0
and the length of the string, specifying the offset into the string of the first character to include in the returned substring.indexEnd
0
and the length of the string, which specifies the offset into the string of the first character not to include in the returned substring.A new string containing the extracted section of the given string.
substring()
extracts characters from indexStart
up to but not including indexEnd
. In particular:
indexStart
equals indexEnd
, substring()
returns an empty string.indexEnd
is omitted, substring()
extracts characters to the end of the string.NaN
, it is treated as if it were 0.stringName.length
, it is treated as if it were stringName.length
.If indexStart
is greater than indexEnd
, then the effect of substring()
is as if the two arguments were swapped; for example, str.substring(1, 0) == str.substring(0, 1)
.
substring()
The following example uses substring()
to display characters from the string 'Mozilla'
:
var anyString = 'Mozilla'; // Displays 'Moz' console.log(anyString.substring(0, 3)); console.log(anyString.substring(3, 0)); // Displays 'lla' console.log(anyString.substring(4, 7)); console.log(anyString.substring(4)); console.log(anyString.substring(7, 4)); // Displays 'Mozill' console.log(anyString.substring(0, 6)); // Displays 'Mozilla' console.log(anyString.substring(0, 7)); console.log(anyString.substring(0, 10));
substring()
with length
propertyThe following example uses the substring()
method and length
property to extract the last characters of a particular string. This method may be easier to remember, given that you don't need to know the starting and ending indices as you would in the above examples.
// Displays 'illa' the last 4 characters var anyString = 'Mozilla'; var anyString4 = anyString.substring(anyString.length - 4); console.log(anyString4); // Displays 'zilla' the last 5 characters var anyString = 'Mozilla'; var anyString5 = anyString.substring(anyString.length - 5); console.log(anyString5);
The following example replaces a substring within a string. It will replace both individual characters and substrings. The function call at the end of the example changes the string 'Brave New World'
into 'Brave New Web'
.
// Replaces oldS with newS in the string fullS function replaceString(oldS, newS, fullS) { for (var i = 0; i < fullS.length; ++i) { if (fullS.substring(i, i + oldS.length) == oldS) { fullS = fullS.substring(0, i) + newS + fullS.substring(i + oldS.length, fullS.length); } } return fullS; } replaceString('World', 'Web', 'Brave New World');
Note that this can result in an infinite loop if oldS
is itself a substring of newS
— for example, if you attempted to replace 'World' with 'OtherWorld' here. A better method for replacing strings is as follows:
function replaceString(oldS, newS, fullS) { return fullS.split(oldS).join(newS); }
The code above serves as an example for substring operations. If you need to replace substrings, most of the time you will want to use String.prototype.replace()
.
Specification | Status | Comment |
---|---|---|
ECMAScript 1st Edition (ECMA-262) | Standard | Implemented in JavaScript 1.0. |
ECMAScript 5.1 (ECMA-262) The definition of 'String.prototype.substring' in that specification. | Standard | |
ECMAScript 2015 (6th Edition, ECMA-262) The definition of 'String.prototype.substring' in that specification. | Standard | |
ECMAScript 2017 Draft (ECMA-262) The definition of 'String.prototype.substring' in that specification. | Draft |
Feature | Chrome | Firefox (Gecko) | Internet Explorer | Opera | Safari |
---|---|---|---|---|---|
Basic support | (Yes) | (Yes) | (Yes) | (Yes) | (Yes) |
Feature | Android | Chrome for Android | Firefox Mobile (Gecko) | IE Mobile | Opera Mobile | Safari Mobile |
---|---|---|---|---|---|---|
Basic support | (Yes) | (Yes) | (Yes) | (Yes) | (Yes) | (Yes) |
© 2005–2017 Mozilla Developer Network and individual contributors.
Licensed under the Creative Commons Attribution-ShareAlike License v2.5 or later.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/substring