The lastIndexOf()
method returns the last index at which a given element can be found in the array, or -1 if it is not present. The array is searched backwards, starting at fromIndex
.
var numbers = [2, 5, 9, 2]; numbers.lastIndexOf(2); // 3 numbers.lastIndexOf(7); // -1
arr.lastIndexOf(searchElement) arr.lastIndexOf(searchElement, fromIndex)
searchElement
fromIndex
Optional
arr.length - 1
), i.e. the whole array will be searched. If the index is greater than or equal to the length of the array, the whole array will be searched. If negative, it is taken as the offset from the end of the array. Note that even when the index is negative, the array is still searched from back to front. If the calculated index is less than 0, -1 is returned, i.e. the array will not be searched.The last index of the element in the array; -1 if not found.
lastIndexOf
compares searchElement
to elements of the Array using strict equality (the same method used by the ===, or triple-equals, operator).
lastIndexOf
The following example uses lastIndexOf
to locate values in an array.
var numbers = [2, 5, 9, 2]; numbers.lastIndexOf(2); // 3 numbers.lastIndexOf(7); // -1 numbers.lastIndexOf(2, 3); // 3 numbers.lastIndexOf(2, 2); // 0 numbers.lastIndexOf(2, -2); // 0 numbers.lastIndexOf(2, -1); // 3
The following example uses lastIndexOf
to find all the indices of an element in a given array, using push
to add them to another array as they are found.
var indices = []; var array = ['a', 'b', 'a', 'c', 'a', 'd']; var element = 'a'; var idx = array.lastIndexOf(element); while (idx != -1) { indices.push(idx); idx = (idx > 0 ? array.lastIndexOf(element, idx - 1) : -1); } console.log(indices); // [4, 2, 0]
Note that we have to handle the case idx == 0
separately here because the element will always be found regardless of the fromIndex
parameter if it is the first element of the array. This is different from the indexOf
method.
lastIndexOf
was added to the ECMA-262 standard in the 5th edition; as such it may not be present in other implementations of the standard. You can work around this by inserting the following code at the beginning of your scripts, allowing use of lastIndexOf
in implementations which do not natively support it. This algorithm is exactly the one specified in ECMA-262, 5th edition, assuming Object
, TypeError
, Number
, Math.floor
, Math.abs
, and Math.min
have their original values.
// Production steps of ECMA-262, Edition 5, 15.4.4.15 // Reference: http://es5.github.io/#x15.4.4.15 if (!Array.prototype.lastIndexOf) { Array.prototype.lastIndexOf = function(searchElement /*, fromIndex*/) { 'use strict'; if (this === void 0 || this === null) { throw new TypeError(); } var n, k, t = Object(this), len = t.length >>> 0; if (len === 0) { return -1; } n = len - 1; if (arguments.length > 1) { n = Number(arguments[1]); if (n != n) { n = 0; } else if (n != 0 && n != (1 / 0) && n != -(1 / 0)) { n = (n > 0 || -1) * Math.floor(Math.abs(n)); } } for (k = n >= 0 ? Math.min(n, len - 1) : len - Math.abs(n); k >= 0; k--) { if (k in t && t[k] === searchElement) { return k; } } return -1; }; }
Again, note that this implementation aims for absolute compatibility with lastIndexOf
in Firefox and the SpiderMonkey JavaScript engine, including in several cases which are arguably edge cases. If you intend to use this in real-world applications, you may be able to calculate from
with less complicated code if you ignore those cases.
Specification | Status | Comment |
---|---|---|
ECMAScript 5.1 (ECMA-262) The definition of 'Array.prototype.lastIndexOf' in that specification. | Standard | Initial definition. Implemented in JavaScript 1.6. |
ECMAScript 2015 (6th Edition, ECMA-262) The definition of 'Array.prototype.lastIndexOf' in that specification. | Standard | |
ECMAScript 2017 Draft (ECMA-262) The definition of 'Array.prototype.lastIndexOf' in that specification. | Draft |
Feature | Chrome | Firefox (Gecko) | Internet Explorer | Opera | Safari |
---|---|---|---|---|---|
Basic support | (Yes) | (Yes) | 9 | (Yes) | (Yes) |
Feature | Android | Chrome for Android | Firefox Mobile (Gecko) | IE Mobile | Opera Mobile | Safari Mobile |
---|---|---|---|---|---|---|
Basic support | (Yes) | (Yes) | (Yes) | (Yes) | (Yes) | (Yes) |
-0
. For example, [0].lastIndexOf(0, -0)
will now always return +0
(bug 1242043).
© 2005–2017 Mozilla Developer Network and individual contributors.
Licensed under the Creative Commons Attribution-ShareAlike License v2.5 or later.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/lastIndexOf