std::conjunction

template<class... B>
struct conjunction;

Forms the logical conjunction of the type traits B..., effectively performing a logical AND on the sequence of traits.

The BaseCharacteristic of a specialization std::conjunction<B1, ..., BN> is the first Bi for which Bi::value == false, or if every Bi::value != false, the BaseCharacteristic is BN.

If sizeof...(B) == 0, the BaseCharacteristic is std::true_type.

Conjunction is short-circuiting: if there is a template type argument Bi with Bi::value == false, then instantiating conjunction<B1, ..., BN>::value does not require the instantiation of Bj::value for j > i.

Template parameters

Helper variable template

template<class... B>
constexpr bool conjunction_v = conjunction<B...>::value;

Possible implementation

template<class...> struct conjunction : std::true_type { };
template<class B1> struct conjunction<B1> : B1 { };
template<class B1, class... Bn>
struct conjunction<B1, Bn...> : std::conditional_t<B1::value != false, conjunction<Bn...>, B1>  {};

Notes

A specialization of conjunction does not necessarily have a BaseCharacteristic of either std::true_type or std::false_type: it simply inherits the base characteristic of the first B whose ::value, converted to bool, is false, or the base characteristic of the very last B when all of them convert to true. For example, std::conjunction<std::integral_constant<int, 2>, std::integral_constant<int, 4>>::value is 4.

Example

#include <iostream>
#include <type_traits>
 
// func is enabled if all Ts... have the same type as T
template<typename T, typename... Ts>
std::enable_if_t<std::conjunction_v<std::is_same<T, Ts>...>>
func(T, Ts...) {
    std::cout << "all types in pack are T\n";
}
 
// otherwise
template<typename T, typename... Ts>
std::enable_if_t<!std::conjunction_v<std::is_same<T, Ts>...>>
func(T, Ts...) {
    std::cout << "not all types in pack are T\n";
}
 
int main() {
    func(1, 2, 3);
    func(1, 2, "hello!");
}

all types in pack are T
not all types in pack are T

See also