C++ programs create, destroy, refer to, access, and manipulate objects.
An object, in C++, is a region of storage that has.
The following entities are not objects: value, reference, function, enumerator, type, class member, bit-field, template, template specialization, namespace, parameter pack, and this
.
A variable is an object or a reference that is not a non-static data member.
Objects are created by definitions, new-expressions, throw-expressions, when changing the active member of a union, and where temporary objects are required.
For an object of type T
, object representation is the sequence of sizeof(T)
objects of type unsigned char
beginning at the same address as the T
object.
The value representation of an object is the set of bits that hold the value of its type T
.
For TriviallyCopyable
types, value representation is a part of the object representation, which means that copying the bytes occupied by the object in the storage is sufficient to produce another object with the same value (except if the value is a trap representation of its type and loading it into the CPU raises a hardware exception, such as SNaN ("signalling not-a-number") floating-point values or NaT ("not-a-thing") integers).
The reverse is not necessarily true: two objects of TriviallyCopyable
type with different object representations may represent the same value. For example, multiple floating-point bit patterns represent the same special value NaN. More commonly, some bits of the object representation may not participate in the value representation at all; such bits may be padding introduced to satisfy alignment requirements, bit field sizes, etc.
#include <cassert> struct S { char c; // 1 byte value // 3 bytes padding float f; // 4 bytes value bool operator==(const S& arg) const { // value-based equality return c == arg.c && f == arg.f; } }; assert(sizeof(S) == 8); S s1 = {'a', 3.14}; S s2 = s1; reinterpret_cast<char*>(&s1)[2] = 'b'; // change 2nd byte assert(s1 == s2); // value did not change
For the objects of type char
, signed char
, and unsigned char
(unless they are oversize bit fields), every bit of the object representation is required to participate in the value representation and each possible bit pattern represents a distinct value (no padding, trap bits, or multiple representations allowed).
An object can contain other objects, which are called subobjects. These include.
An object that is not a subobject of another object is called complete object.
Complete objects, member objects, and array elements are also known as most derived objects, to distinguish them from base class subobjects. The size of a most derived object that is not a bit field is required to be non-zero (the size of a base class subobject may be zero: see empty base optimization).
Any two objects with overlapping lifetimes (that are not bit fields) are guaranteed to have different addresses unless one of them is a subobject of another or provides storage for another, or if they are subobjects of different type within the same complete object, and one of them is a zero-size base.
static const char c1 = ’x’; static const char c2 = ’x’; assert(&c1 != &c2); // same values, different addresses
Objects of class type that declare or inherit at least one virtual function are polymorphic objects. Within each polymorphic object, the implementation stores additional information (in every existing implementation, it is one pointer unless optimized out), which is used by virtual function calls and by the RTTI features (dynamic_cast and typeid) to determine, at run time, the type with which the object was created, regardless of the expression it is used in.
For non-polymorphic objects, the interpretation of the value is determined from the expression in which the object is used, and is decided at compile time.
#include <iostream> #include <typeinfo> struct Base1 { // polymorphic type: declares a virtual member virtual ~Base1() {} }; struct Derived1 : Base1 { // polymorphic type: inherits a virtual member }; struct Base2 { // non-polymorphic type }; struct Derived2 : Base2 { // non-polymorphic type }; int main() { Derived1 obj1; // object1 created with type Derived1 Derived2 obj2; // object2 created with type Derived2 Base1& b1 = obj1; // b1 refers to the object obj1 Base2& b2 = obj2; // b2 refers to the object obj2 std::cout << "Expression type of b1: " << typeid(decltype(b1)).name() << ' ' << "Expression type of b2: " << typeid(decltype(b2)).name() << '\n' << "Object type of b1: " << typeid(b1).name() << ' ' << "Object type of b2: " << typeid(b2).name() << '\n' << "size of b1: " << sizeof b1 << ' ' << "size of b2: " << sizeof b2 << '\n'; }
Output:
Expression type of b1: Base1 Expression type of b2: Base2 Object type of b1: Derived1 Object type of b2: Base2 size of b1: 8 size of b2: 1
Accessing an object using an expression of a type other than the type with which it was created is undefined behavior in many cases, see reinterpret_cast for the list of exceptions and examples.
Every object type has the property called alignment requirement, which is an integer value (of type std::size_t
, always a power of 2) representing the number of bytes between successive addresses at which objects of this type can be allocated. The alignment requirement of a type can be queried with alignof or std::alignment_of
. The pointer alignment function std::align
can be used to obtain a suitably-aligned pointer within some buffer, and std::aligned_storage
can be used to obtain suitably-aligned storage.
Each object type imposes its alignment requirement on every object of that type; stricter alignment (with larger alignment requirement) can be requested using alignas.
In order to satisfy alignment requirements of all non-static members of a class, padding may be inserted after some of its members.
#include <iostream> // objects of type S can be allocated at any address // because both S.a and S.b can be allocated at any address struct S { char a; // size: 1, alignment: 1 char b; // size: 1, alignment: 1 }; // size: 2, alignment: 1 // objects of type X must be allocated at 4-byte boundaries // because X.n must be allocated at 4-byte boundaries // because int's alignment requirement is (usually) 4 struct X { int n; // size: 4, alignment: 4 char c; // size: 1, alignment: 1 // three bytes padding }; // size: 8, alignment: 4 int main() { std::cout << "sizeof(S) = " << sizeof(S) << " alignof(S) = " << alignof(S) << '\n'; std::cout << "sizeof(X) = " << sizeof(X) << " alignof(X) = " << alignof(X) << '\n'; }
Output:
sizeof(S) = 2 alignof(S) = 1 sizeof(X) = 8 alignof(X) = 4
The weakest alignment (the smallest alignment requirement) is the alignment of char
, signed char
, and unsigned char
, which equals 1; the largest fundamental alignment of any type is the alignment of std::max_align_t
. If a type's alignment is made stricter (larger) than std::max_align_t
using alignas, it is known as a type with extended alignment requirement. A type whose alignment is extended or a class type whose non-static data member has extended alignment is an over-aligned type. It is implementation-defined if new-expression, std::allocator::allocate
, and std::get_temporary_buffer
support over-aligned types. Allocator
s instantiated with over-aligned types are allowed to fail to instantiate at compile time, to throw std::bad_alloc
at runtime, to silently ignore unsupported alignment requirement, or to handle them correctly.
C documentation for object |
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