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std::move

Defined in header `<algorithm>`
template< class InputIt, class OutputIt > OutputIt move( InputIt first, InputIt last, OutputIt d_first );	(1)	(since C++11)
template< class ExecutionPolicy, class InputIt, class OutputIt > OutputIt move( ExecutionPolicy&& policy, InputIt first, InputIt last, OutputIt d_first );	(2)	(since C++17)

Defined in header <algorithm>

template< class InputIt, class OutputIt >
OutputIt move( InputIt first, InputIt last, OutputIt d_first );

(1)

(since C++11)

template< class ExecutionPolicy, class InputIt, class OutputIt >
OutputIt move( ExecutionPolicy&& policy, InputIt first, InputIt last, OutputIt d_first );

(2)

(since C++17)

1) Moves the elements in the range [first, last), to another range beginning at d_first. After this operation the elements in the moved-from range will still contain valid values of the appropriate type, but not necessarily the same values as before the move.

2) Same as (1), but executed according to policy. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true

Parameters

first, last	-	the range of elements to move
d_first	-	the beginning of the destination range. If `d_first` is within `[first, last)`, `std::move_backward` must be used instead of std::move.
policy	-	the execution policy to use. See execution policy for details.
Type requirements
- `InputIt` must meet the requirements of `InputIterator`.
- `OutputIt` must meet the requirements of `OutputIterator`.

Return value

Output iterator to the element past the last element moved (d_first + (last - first)).

Complexity

Exactly last - first move assignments.

Exceptions

The overload with a template parameter named ExecutionPolicy reports errors as follows:

If execution of a function invoked as part of the algorithm throws an exception, std::terminate is called.
If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation

template<class InputIt, class OutputIt>
OutputIt move(InputIt first, InputIt last, OutputIt d_first)
{
    while (first != last) {
        *d_first++ = std::move(*first++);
    }
    return d_first;
}

Notes

When moving overlapping ranges, std::move is appropriate when moving to the left (beginning of the destination range is outside the source range) while std::move_backward is appropriate when moving to the right (end of the destination range is outside the source range).

Example

The following code moves thread objects (which themselves are not copyable) from one container to another.

#include <iostream>
#include <vector>
#include <list>
#include <iterator>
#include <thread>
#include <chrono>
 
void f(int n)
{
    std::this_thread::sleep_for(std::chrono::seconds(n));
    std::cout << "thread " << n << " ended" << '\n';
}
 
int main() 
{
    std::vector<std::thread> v;
    v.emplace_back(f, 1);
    v.emplace_back(f, 2);
    v.emplace_back(f, 3);
    std::list<std::thread> l;
    // copy() would not compile, because std::thread is noncopyable
 
    std::move(v.begin(), v.end(), std::back_inserter(l)); 
    for (auto& t : l) t.join();
}

Output:

thread 1 ended
thread 2 ended
thread 3 ended

move_backward (C++11)	moves a range of elements to a new location in backwards order (function template)
move (C++11)	obtains an rvalue reference (function template)