Defined in header
<algorithm> | ||
---|---|---|
template< class InputIt1, class InputIt2, class OutputIt > OutputIt merge( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first ); | (1) | |
template< class ExecutionPolicy, class InputIt1, class InputIt2, class OutputIt > OutputIt merge( ExecutionPolicy&& policy, InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first ); | (2) | (since C++17) |
template< class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt merge( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp ); | (3) | |
template< class ExecutionPolicy, class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt merge( ExecutionPolicy&& policy, InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp ); | (4) | (since C++17) |
Merges two sorted ranges [first1, last1)
and [first2, last2)
into one sorted range beginning at d_first
.
operator<
.comp
.policy
. These overloads do not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>>
is trueFor equivalent elements in the original two ranges, the elements from the first range (preserving their original order) precede the elements from the second range (preserving their original order).
The behavior is undefined if the destination range overlaps either of the input ranges (the input ranges may overlap each other).
first1, last1 | - | the first range of elements to merge |
first2, last2 | - | the second range of elements to merge |
d_first | - | the beginning of the destination range |
policy | - | the execution policy to use. See execution policy for details. |
comp | - | comparison function object (i.e. an object that satisfies the requirements of Compare ) which returns true if the first argument is less than (i.e. is ordered before) the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
Type requirements | ||
-
InputIt1 must meet the requirements of InputIterator . |
||
-
InputIt2 must meet the requirements of InputIterator . |
||
-
OutputIt must meet the requirements of OutputIterator . |
An output iterator to element past the last element copied.
At most std::distance(first1, last1) + std::distance(first2, last2) - 1
comparisons.
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
std::terminate
is called. std::bad_alloc
is thrown. This algorithm performs a similar task as std::set_union
does. Both consume two sorted input ranges and produce a sorted output with elements from both inputs. The difference between these two algorithms is with handling values from both input ranges which compare equivalent (see notes on LessThanComparable
). If any equivalent values appeared n
times in the first range and m
times in the second, std::merge
would output all n+m
occurrences whereas std::set_union
would output std::max(n, m)
ones only. So std::merge
outputs exactly std::distance(first1, last1) + std::distance(first2, last2)
values and std::set_union
may produce less.
First version |
---|
template<class InputIt1, class InputIt2, class OutputIt> OutputIt merge(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first) { for (; first1 != last1; ++d_first) { if (first2 == last2) { return std::copy(first1, last1, d_first); } if (*first2 < *first1) { *d_first = *first2; ++first2; } else { *d_first = *first1; ++first1; } } return std::copy(first2, last2, d_first); } |
Second version |
template<class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt merge(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp) { for (; first1 != last1; ++d_first) { if (first2 == last2) { return std::copy(first1, last1, d_first); } if (comp(*first2, *first1)) { *d_first = *first2; ++first2; } else { *d_first = *first1; ++first1; } } return std::copy(first2, last2, d_first); } |
#include <iostream> #include <iterator> #include <algorithm> #include <vector> #include <random> #include <functional> int main() { // fill the vectors with random numbers std::random_device rd; std::mt19937 mt(rd()); std::uniform_int_distribution<> dis(0, 9); std::vector<int> v1(10), v2(10); std::generate(v1.begin(), v1.end(), std::bind(dis, std::ref(mt))); std::generate(v2.begin(), v2.end(), std::bind(dis, std::ref(mt))); // sort std::sort(v1.begin(), v1.end()); std::sort(v2.begin(), v2.end()); // output v1 std::cout << "v1 : "; std::copy(v1.begin(), v1.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; // output v2 std::cout << "v2 : "; std::copy(v2.begin(), v2.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; // merge std::vector<int> dst; std::merge(v1.begin(), v1.end(), v2.begin(), v2.end(), std::back_inserter(dst)); // output std::cout << "dst: "; std::copy(dst.begin(), dst.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; }
Possible output:
v1 : 0 1 3 4 4 5 5 8 8 9 v2 : 0 2 2 3 6 6 8 8 8 9 dst: 0 0 1 2 2 3 3 4 4 5 5 6 6 8 8 8 8 8 9 9
merges two ordered ranges in-place (function template) |
|
computes the union of two sets (function template) |
|
sorts a range into ascending order (function template) |
|
sorts a range of elements while preserving order between equal elements (function template) |
|
(parallelism TS)
| parallelized version of std::merge (function template) |
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