Defined in header <stdlib.h> | ||
---|---|---|
void* calloc( size_t num, size_t size ); |
Allocates memory for an array of num
objects of size size
and initializes all bytes in the allocated storage to zero.
If allocation succeeds, returns a pointer to the lowest (first) byte in the allocated memory block that is suitably aligned for any object type.
If size
is zero, the behavior is implementation defined (null pointer may be returned, or some non-null pointer may be returned that may not be used to access storage).
A previous call to | (since C11) |
num | - | number of objects |
size | - | size of each object |
On success, returns the pointer to the beginning of newly allocated memory. The returned pointer must be deallocated with free()
or realloc()
.
On failure, returns a null pointer.
Due to the alignment requirements, the number of allocated bytes is not necessarily equal to num*size
.
Initialization to all bits zero does not guarantee that a floating-point or a pointer would be initialized to 0.0 and the null pointer value, respectively (although that is true on all common platforms).
Originally (in C89), support for zero size was added to accommodate code such as.
OBJ *p = calloc(0, sizeof(OBJ)); // "zero-length" placeholder ... while(1) { p = realloc(p, c * sizeof(OBJ)); // reallocations until size settles ... // code that may change c or break out of loop }
#include <stdio.h> #include <stdlib.h> int main(void) { int *p1 = calloc(4, sizeof(int)); // allocate and zero out an array of 4 int int *p2 = calloc(1, sizeof(int[4])); // same, naming the array type directly int *p3 = calloc(4, sizeof *p3); // same, without repeating the type name if(p2) { for(int n=0; n<4; ++n) // print the array printf("p2[%d] == %d\n", n, p2[n]); } free(p1); free(p2); free(p3); }
Output:
p2[0] == 0 p2[1] == 0 p2[2] == 0 p2[3] == 0
C++ documentation for calloc |
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